3j^2-19j-14=0

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Solution for 3j^2-19j-14=0 equation:


Simplifying
3j2 + -19j + -14 = 0

Reorder the terms:
-14 + -19j + 3j2 = 0

Solving
-14 + -19j + 3j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-2 + -3j)(7 + -1j) = 0

Subproblem 1

Set the factor '(-2 + -3j)' equal to zero and attempt to solve: Simplifying -2 + -3j = 0 Solving -2 + -3j = 0 Move all terms containing j to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -3j = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -3j = 0 + 2 -3j = 0 + 2 Combine like terms: 0 + 2 = 2 -3j = 2 Divide each side by '-3'. j = -0.6666666667 Simplifying j = -0.6666666667

Subproblem 2

Set the factor '(7 + -1j)' equal to zero and attempt to solve: Simplifying 7 + -1j = 0 Solving 7 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1j = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1j = 0 + -7 -1j = 0 + -7 Combine like terms: 0 + -7 = -7 -1j = -7 Divide each side by '-1'. j = 7 Simplifying j = 7

Solution

j = {-0.6666666667, 7}

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